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4(x^2-8x-425)=0
We multiply parentheses
4x^2-32x-1700=0
a = 4; b = -32; c = -1700;
Δ = b2-4ac
Δ = -322-4·4·(-1700)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28224}=168$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-168}{2*4}=\frac{-136}{8} =-17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+168}{2*4}=\frac{200}{8} =25 $
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